Code:
/* This short function is used to print out the contents of a
* specified array.
*/
void printArr(int *arr, int length){
for(int i = 0; i < length; i++){
printf("%d ", arr[i]);
}
printf("\n");
}
int main(void) {
int *arr,(*a)[ARR_LENGTH], (*b)[ARR_LENGTH], (*c)[ARR_LENGTH], (*d)[ARR_LENGTH], (*e)[ARR_LENGTH], *t;
int a_arr[ARR_LENGTH] = {1,2,3,4,5,6,7,8,9,10};
int b_arr[ARR_LENGTH] = {5,6,7,8,9,10,1,2,3,4};
int c_arr[ARR_LENGTH] = {6,7,8,9,10,1,2,3,4,5};
int d_arr[ARR_LENGTH] = {3,4,5,6,7,8,9,10,1,2};
int e_arr[ARR_LENGTH] = {9,10,1,2,3,4,5,6,7,8};
a = &a_arr;
b = &b_arr;
c = &c_arr;
d = &d_arr;
e = &e_arr;
int *t_arr[5] = {*a, *b, *c, *d, *e};
//t = &t_arr[0];
for(int k = 0; k < 5; k++){
//arr = t + k;
arr = &t_arr[k];
printf("\nthe array is:\n");
printArr(arr, ARR_LENGTH);
/*for(int j = 0; j < 10; j++){
int target = j + 1;
int count = 0;
int found = rotated_bin_search(arr, ARR_LENGTH, target, &arr[0], &arr[9], count);
if(found!=0)
printf ("\n%d was found in the array\n", found);
}*/
}
return 1;
}
Thanks!